Two OF THE SAME IBL (P1) bred together equals P2, which ends up being the same as P1 due as it is true breeding.
P1 mean the initial parent, the starting point. The two patients zero.
But you’re just describing in the example a F(n+1). If you’re in F2, then you end with F3.
F2, F3, F4 etc … is just the other manner to say IBL with more accuracy (with the number of the generation).
But it don’t avoid the battle between the twos P1 and theyr respective ancestors in the successive offspring.
Two DIFFERENT P1 (P1a x P1b) equals F1 Hybrid (P1ab), which would contain mixed traits of the two P1 and display heterosis, or hybrid vigor.
Exactly.
Two different F1 Hybrids crossed equals F2 Cross
No, they are F1 and have the heterosis btw.
Two different H1 crossed [(P1a x P1b)(P1a x P1c)] x [(P1b x P1c)(P1c x P1d)]= H2
No. F1a x F1b = F1ab, not F3.
Two same H1 [(P1ab x P1ac)x(P1ab x P1ac)] crossed begins the inbreeding process which can result in a new IBL over many generations.
You are just describing a F2 with useless complications, but yes.