I was going through a recipe for STS preparation to try and figure out what the concentration of STS I should be shooting for in the final, applied solution. I wanted to check my math and see if my assessment of preparing STS made sense:
Part A (AgNO3 Stock Soln)
- Fill the pyrex 2-cup measure to the 500ml line with r/o water
- Measure .5 Grams of Silver Nitrate using the digital scale
- Slowly pour the silver nitrate crystals in to the 500ml of r/o water while stirring
- Stir until dissolved (15 seconds)
- Pour the Sodium Thiosulfate solution in to a 500ml brown glass bottle and cap it tightly
Silver Nitrate’s molar mass is 169.873 g/mol, so:
((0.5 g/169.873 g/mol)/0.5 L) = 0.005887 molar AgNO3 = 5.887 millimolar AgNO3
Part B (Na2O3S2 Stock Soln)
- Fill the pyrex 2-cup measure to the 500ml mark with r/o water
- Measure 2.5 Grams of Sodium Thiosulfate Anhydrous OR 3.9Grams of Sodium Thiosulfate Pentahydrate
- Add the Sodium Thiosulfate to the r/o water while stirring
- Stir until completely dissolved (30-45 seconds)
- Pour the Sodium Thiosulfate solution in to a 500ml brown glass bottle and cap it tightly
Sodium Thiosulfate (anhydrous) mass is 158.11 g/mol, so:
((2.5 g/158.11 g/mol)/0.5 L) = 0.03162 molar Na2O3S2 = 31.62 millimolar Na2O3S2
Clearly the formula is made to reach the silver nitrate completely with excess sodium thiosulfate. Further instructions from the post are for preparing 1 quart of solution ~946 mL, mixing 50 mL of each stock solution together and then diluting to volume. Given that the limiting reagent will be silver nitrate, assuming it reacts completely the concentration of STS in the final product will be:
(M1)(V1) = (M2)(V2); (50 mL)(5.887 millimolar) = (946 mL)(“X” mM)
X = (50)(5.887)/(946) = 0.3112 mM, or around 3 *(10^-4) M STS solution.
So does my math look solid? Is the general formula to slowly react a 5+ millimolar solution of silver nitrate with excess sodium thiosulfate and dilute to 0.3 millimolar concentration?
Edit: It’s probably actually around a 0.15 millimolar solution (or less, with loss) because each silver nitrate molecule contains one silver atom and each silver thiosulfate molecule contains two silver atoms.